(16x^2-5)-(4x^2+10)=0

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Solution for (16x^2-5)-(4x^2+10)=0 equation:


Simplifying
(16x2 + -5) + -1(4x2 + 10) = 0

Reorder the terms:
(-5 + 16x2) + -1(4x2 + 10) = 0

Remove parenthesis around (-5 + 16x2)
-5 + 16x2 + -1(4x2 + 10) = 0

Reorder the terms:
-5 + 16x2 + -1(10 + 4x2) = 0
-5 + 16x2 + (10 * -1 + 4x2 * -1) = 0
-5 + 16x2 + (-10 + -4x2) = 0

Reorder the terms:
-5 + -10 + 16x2 + -4x2 = 0

Combine like terms: -5 + -10 = -15
-15 + 16x2 + -4x2 = 0

Combine like terms: 16x2 + -4x2 = 12x2
-15 + 12x2 = 0

Solving
-15 + 12x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 15 + 12x2 = 0 + 15

Combine like terms: -15 + 15 = 0
0 + 12x2 = 0 + 15
12x2 = 0 + 15

Combine like terms: 0 + 15 = 15
12x2 = 15

Divide each side by '12'.
x2 = 1.25

Simplifying
x2 = 1.25

Take the square root of each side:
x = {-1.118033989, 1.118033989}

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